How to calculate Third Largest numbet in java from a Unsorted Array

Count Number of characters in a Given String

SOURCE : ThirdLargest.java

public class ThirdLargest {

	public static void main(String[] args) {

		int[] num = { 0, -87, 65, 87, 98, 76, 56 };

		ThirdLargest tt = new ThirdLargest();
		tt.max(num);

	}

	private void max(int[] num) {

		int maxone = 0;
		int maxtwo = 0;
		int maxthree = 0;

		try {
			for (int n : num) {
				if (maxone < n) {
					maxthree = maxtwo;
					maxtwo = maxone;
					maxone = n;

				} else if (maxtwo < n) {
					maxthree = maxtwo;
					maxtwo = n;

				} else if (maxthree < n) {
					maxthree = n;
				}

			}
		} catch (Exception e) {
			// TODO: handle exception
		}

		System.out.println("1st largest=:" + maxone);
		System.out.println("2nd largest=" + maxtwo);
		System.out.println("3rd largest=:" + maxthree);
	}
}

OUTPUT

1st largest=:98
2nd largest=87
3rd largest=:76

Hi, I have written and developed this post so that most of people will be benefited. I'm committed to provide easy and in-depth tutorials on various technologies.I hope it will help you a lot.
- Sandeep Kumar D

Follow Me @Google+

SHARE

Onlinecodegeek