How to find sum of Digits of Given Number and Number is Armstrong Number or Not

How to find sum of Digits of Given Number and Number is Armstrong Number or Not

SOURCE : SumOfDigits.java

public class SumOfDigits {

	static int sum = 0;
	static int sum1 = 0;

	public static void main(String[] args) {

		SumOfDigits sdm = new SumOfDigits();
		int n = 371;
		System.out.println("sum of digits  :" + sdm.sumofdig(371));

		sdm.armstrong(371);

		if (sum1 == n) {
			System.out.println("given number is armstrong ");
		} else
			System.out.println("given number is not armstrong");

	}

	public int armstrong(int numb) {

		if (numb == 0) {
			return sum1;
		} else {

			sum1 += ((numb % 10) * (numb % 10) * (numb % 10));

			armstrong(numb / 10);

		}

		return sum1;
	}

	public int sumofdig(int num) {

		if (num == 0) {

			return sum;
		} else {
			sum += (num % 10);
			sumofdig(num / 10);

		}

		return sum;
	}

}

INPUT

	371

OUTPUT

sum of digits  :11
given number is armstrong 

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